A solution containing 10.2 g of glycerine per litre is found to be isotonic with 2% solution of glucose. Calculate the molar mass of glycerine.

Saurav KumarNewbie

# A solution containing 10.2 g of glycerine per litre is found to be isotonic with 2% solution of glucose. Calculate the molar mass of glycerine.

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This answer was edited.Since both solutions are isotonic so,

Π1=Π2 {osmotic pressure same}

C1RT=C2RT

C1=C2

10.2/Mw×1 = 2×1000/180×100 {2% glucose= 2g in 100 ml solution}

10.2×100×180 / 2000 =Mw⇒ Molecular weight of glycerin =91.8g

## Satyam 🔥🔥🔥

Π1=Π2 {osmotic pressure same}

C1RT=C2RT

C1=C2

10.2/Mw×1 = 2×1000/180×100 {2% glucose= 2g in 100 ml solution}

## 10.2×100×180 / 2000 =Mw⇒ Molecular weight of glycerin =91.8g

## Satyam 🔥🔥🔥

This answer was edited.

Since both solutions are isotonic so,

Π1=Π2 {osmotic pressure same}

C1RT=C2RT

C1=C2

10.2/Mw×1 = 2×1000/180×100 {2% glucose= 2g in 100 ml solution}

10.2×100×180 / 2000 =Mw⇒ Molecular weight of glycerin =91.8g

## Adityakumar

This answer was edited.Since both solutions are isotonic so,

Π1=Π2 {osmotic pressure same}

C1RT=C2RT

C1=C2

10.2/Mw×1 = 2×1000/180×100 {2% glucose= 2g in 100 ml solution}

10.2×100×180 / 2000 =Mw⇒ Molecular weight of glycerin =91.8g

## Salman

## Molecular weight of glycerin =91.8g

## Shivansh Preet

Given termstotal glycerin content in the solution = 10.2 g/lglucose solution = 2%Since, both are isotonic thenpie glycerin = pie glucose (osmotic pressure same)C1RT = C2RTC1=C2 (Since, RT cancelled out)10.2 / Mw X 1 = 2 X 1000 / 100 X 180Mw = 10.2 X 100 X 180 / 2000Glycerin molecular weight = 91.8g