A cyclist travels from centre O of a circular park of radius 1 km and reaches point P. After cycling along 1/4 th of the circumference along PQ, he returns to the centre of the park along QO. If the total time taken is 10 minutes, calculate (i) net displacement (ii) average velocity and (iii) average speed of the cyclist.

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# A cyclist travels from centre O of a circular park of radius 1 km and reaches point P. After cycling along 1/4 th of the circumference along PQ, he returns to the centre of the park along QO. If the total time taken is 10 minutes, calculate (i) net displacement (ii) average velocity and (iii) average speed of the cyclist.

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(1). Zero

(2). Zero

(3). 21.42 km/h

## Satyam 🔥🔥🔥

¢Net displacement is 0 because its initial and final point is same.

2. Average velocity= displacement/time

Average velocity= 0/10 =0

So average velocity is 0.

3. Average speed = total distance/time

=1+1/4(2*22/7*1)+1 / 0.16

=21.42 km/h

## Abul

1. Net displacement is 0 because its initial and final point is same.2. Average velocity= displacement/timeAverage velocity= 0/10 =0So average velocity is 0.3. Average speed = total distance/time=1+1/4(2*22/7*1)+1 / 0.16=21.42 km/h## Salman

1. Net displacement is 0 because its initial and final point is same.2. Average velocity= displacement/timeAverage velocity= 0/10 =0So average velocity is 0.3. Average speed = total distance/time=1+1/4(2*22/7*1)+1 / 0.16=21.42 km/h## Shivansh Preet

1. Net displacement is 0 because its initial and final point is same.2. Average velocity= displacement/timeAverage velocity= 0/10 =0So average velocity is 0.3. Average speed = total distance/time=1+1/4(2*22/7*1)+1 / 0.16=21.42 km/h## Jonny liver

¢Net displacement is 0 because its initial and final point is same.

2. Average velocity= displacement/time

Average velocity= 0/10 =0

So average velocity is 0.

3. Average speed = total distance/time

=1+1/4(2*22/7*1)+1 / 0.16

=21.42 km/h

## DON

1. Net displacement is 0 because its initial and final point is same.

2. Average velocity= displacement/time

Average velocity= 0/10 =0

So average velocity is 0.

3. Average speed = total distance/time

=1+1/4(2*22/7*1)+1 / 0.16

=21.42 km/h

## Ritik kumar

Net displacement is 0 because its initial and final point is same.2. Average velocity= displacement/timeAverage velocity= 0/10 =0So average velocity is 0.3. Average speed = total distance/time=1+1/4(2*22/7*1)+1 / 0.16=21.42 km/h## Ritik kumar

Net displacement is 0 because its initial and final point is same.2. Average velocity= displacement/timeAverage velocity= 0/10 =0So average velocity is 0.3. Average speed = total distance/time=1+1/4(2*22/7*1)+1 / 0.16=21.42 km/h